Odds of "THEODOR KAZNSKI" in 340 CHARACTER ZODIAC CIPHER
Zodiackiller.com Message Board
: Ciphers: Odds of "THEODOR KAZNSKI" in 340 CHARACTER ZODIAC CIPHER| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Tuesday, July 23, 2002 - 01:40 am: |
Hi Folks,
In response to questions by Lapumo, and spurred on by recent
successes of Zander, Bobbitt and others, I finished up something I'd
been working on for some time which I set aside for several months.
Basically I tried to compute, as rigorously as possible the probability that
the 340 Character Cipher contains "close matches" to both THEODORE and
KACZYNSKI. I hope this will help some of our discussions on topics of
coincidences, which are often difficult to resolve because it is difficult
to compute the odds. You can find text at:
http://www.ciw.edu/chris/z/monty.txt
I'm creating a new discussion, because, unlike previous discussion,
the topic of this work is not SOLVING the meaning of the cipher, but
interpreting the cipher-text itsself.
obiwan
| By Zander Kite (Zk) (dialup-65.57.54.213.dial1.nashville1.level3.net - 65.57.54.213) on Tuesday, July 23, 2002 - 07:41 am: |
Obiwan: highly impressive work: You've set the odds on this at 100,000 to 20,000,000 to 1. That's the way I see this too. Very high odds if only coincidence. "Theodore Kaczynski" is communicated plainly in the respective first and last lines. I allowed for the symbol on the last line that strongly resembles a capital "I" to equal "I". Allowing each symbol to be its letter or the one it closely matches: you get: THEODORVPLVVKIOLTGOD and KAZINSKIMDHNPO. That's the standard by which I would set odds on, of course that is essentially what you have done. We are not dealing with a killer who's interested in jail cells, so I wouldn't expect a perfect layout of the killers name. I don't wanna go crazy on this: but the middle of the code is represented by a six-letter 2x3 block. The first letter of that block is "J". There is already a strong case for connecting the two publicity-seeking disaffected killers, Kaczynski and Zodiac. Now, we have two estimates agreeing on 100,000 to 20 million to 1 for Kaczynskis name being communicated in the 340-code. I'm not sure about the odds of a near TK anagram in the opening line. It seems odd though that the word "the" is used. It's an odd phrase and there are 17 letters after it(The Zodiacs number), so it really looks too much like "This is Theodore Kaczynski". I wonder what the odds are on two-publicity-seeking-disaffected-killers using such a similar sentence: Zodiac: In light of recent events, this kind of murder glorification can only be deplorable at best. Kaczynski: We strongly deplore this kind of indisriminate slaughter that occurred in the Oklahoma City event. It must be high odds also.
| By Scott Bullock (Scott_Bullock) (spider-ntc-tc054.proxy.aol.com - 198.81.17.44) on Tuesday, July 23, 2002 - 08:24 am: |
I'll bet the odds of Arthur Leigh Allen's name being found by random chance in the
340-character cipher are even greater than 100,000 to 20,000,000 to 1. Why not work up the
numbers on Allen and see? In fact, why not work up the numbers on numerous suspects,
including Alfred E. Neumann, and then determine the odds?
Biased investigation without a foundation in the factual will only lead to biased answers.
Face it folks, the numbers of interpretations that can be found in the 340-character
cipher are infinite: It will never be solved because it was never meant to be. Otherwise,
it would have been solved by now. At least, that is what can be derived from
Ockham's Razor; a very useful edict when concerning oneself with the 340-character cipher,
in my opinion.
Scott
| By Ray N (Ray_N) (user-38ld82l.dialup.mindspring.com - 209.86.160.85) on Tuesday, July 23, 2002 - 09:55 am: |
Board,
My two cents worth says that there is a major problem with this whole line of inquiry,
with respect to logic. Of course the odds are against finding any one specific name. We
can guess that much. The problem lies in the fact that the name was not "found".
It was haphazardly manipulated into being. It would be different if it was just lying
there or if a particular algorithm was applied without a preconceived expectation that
just happened to produce TK. This is far from what happened.
Although I applaud efforts into code solving, this is not the kind of work that is going
to solve this case. Objective analysis has to be the controlling motivation. Yes, there is
plenty of circumstantial evidence that TK was Zodiac. That should not motivate one to
write his name at the top of a sheet of paper and then start trying to figure out some way
(which involves arbitrary transposition of each and every letter) to arrive at the
predetermined (desired) solution. Of course, once this is achieved, then a search is
commenced into the Zodiac missives for any/all numeric references which can be construed
in some way as intended to describe the actual mechanics that ultimately produced the
"result". This is 180 degrees out of phase with legitimate investigative
techniques. Granted, code work often involves guesswork and unproven precepts, but
manipulation on the level seen by Zander's solution (manipulation of each letter by some
unknown algorithm that only arguably has a definite pattern) stands out in the history of
work in this area. It is no more credible than the Hines solution of the 13-cryptogram.
What's worse is the fact that the solution is unprovable. It relies wholly on some
unknowable range of odds to establish itself as correct. There is not any proof provided
that what Zander offers was the intended solution. If the Z took the trouble to encode his
name here, he certainly would have done it in a way which could be shown not to be subject
to doubt.
As an example of what I'm trying to say, why doesn't someone compute the odds of someone
trying to construct a particular 17 letter phrase when they are allowed to manipulate the
string arbitrarily according to no identifiably fixed pattern? There are plenty of numeric
references which could later be used to back this up, e.g. 0, 2, 3, 4, 6, 7, 8, 9, 10, 11,
12, 13, 14, 20, 27, 37, etc. In short, how could one possibly fail?
Of course, in Zander's solution, the string must also first be carefully anagrammed to one
particular order for which there is no basis other than to succeed in finding TK's name.
Frankly, this is not something that even approaches the general description of legitimate
cryptography.
In my view, Occam's Razor suggests that the last line of cipher text was only provided to
fix the size of that section equal to the others in order to make it impossible to
determine at a glance in which order the full message was written. It is highly probable
that much effort is being expended upon cipher text which is nothing more than dead-end
gibberish.
Well, good luck!
Ray
| By Douglas Oswell (Dowland) (31.philadelphia08rh.16.pa.dial-access.att.net - 12.90.31.31) on Tuesday, July 23, 2002 - 10:01 am: |
Zander, you observe "there is already a strong case for connecting the two
publicity-seeking disaffected killers, Kaczynski and Zodiac." That's precisely why
Obiwan's work here, allied with your observations on the 3-Part Cipher, my own on the
13-Symbol Cipher and the significance of anagramming in "the Zodiac speaking,"
are such powerful elements in connecting Kaczynski to Zodiac. You start with a baseline
that asks what the odds are that two male Caucasian individuals bearing the same
psychological profile and criminal signature are the same, then use that baseline to
factor in the probabilities concerning additional connections. The baseline figure is
going to be exceptionally low to begin with, especially if you factor in the commonalities
in locations and dates. I haven't tried to work it out, but it's probably something like
one in ten million at the very least. You can take that figure and apply the probabilities
Obiwan has come up with, then factor in the 3-Part Cipher and the "Zodiac
speaking" anagram to arrive at a figure that is so ridiculously low that it's almost
not a figure at all. Having done that, you can look at other factors such as the
similarities in style, once again further reducing an infinitesimal number.
Well done, Obiwan. It's refreshing to see someone actually invest some personal time on a
project such as this. Ultimately it will make a lot of difference.
| By Ray N (Ray_N) (user-38ld82l.dialup.mindspring.com - 209.86.160.85) on Tuesday, July 23, 2002 - 10:15 am: |
Doug:
You wrote,
Zander, you observe "there is already a strong case for connecting the two
publicity-seeking disaffected killers, Kaczynski and Zodiac." That's precisely why
Obiwan's work here, allied with your observations on the 3-Part Cipher, my own on the
13-Symbol Cipher and the significance of anagramming in "the Zodiac speaking,"
are such powerful elements in connecting Kaczynski to Zodiac."
This is exactly what I'm talking about. The assumption is that TK is Zodiac, and hence the
search for his name. That's precisely why Obiwan's analysis says nothing, neither for or
against, Zander's solution. You might be impressed, but that doesn't make something real.
Ray
| By Zander Kite (Zk) (dialup-65.58.109.149.dial1.nashville1.level3.net - 65.58.109.149) on Tuesday, July 23, 2002 - 03:27 pm: |
Ray, the odds established here are not for my "Beoriete Methhpiti" solution. I've noticed the trend with you is not to really take the time to analyze what's posted concerning code connections to Ted Kaczynski. I can only guess that you(Scott too)are so convinced that Arthur Leigh Allen was The Zodiac that you find any other approach to be ridiculous. The odds established here by Obiwan deal with uncoded symbols and their frequency of use etc.. Nobody's making up anything. Theodor Kazinski is plainly communicated in the respective first and last lines of the 340-code. For example, a quick count reveals that the symbol "K"(backwards and forwards) appears around 12 times, while the "Z" is used only 4 times. The last line holds 2 K's and one "Z". That is well against the odds. You analzye the rest of the symbols similarly and then you're left with defying great odds like what Obiwan arrived at. Doug, I agree. When you start stacking the odds, the number is no longer realistic, and (in my opinion) one is forced to accept that TK must have been The Z before FC.
| By Ray N (Ray_N) (user-38ldeuh.dialup.mindspring.com - 209.86.187.209) on Tuesday, July 23, 2002 - 04:37 pm: |
Zander,
I read it alright. Every word. And I repeat that it has no bearing on your solution. In
fact, it has no bearing on anything because you have manufactured every occurrence you
claim is plainly communicated. "Plainly communicated" is a concept that we must
have different definitions of. Until you stop playing "let's find Ted's name in the
codes," the board will keep hearing from me on this topic. I'm not trying to disuade
you from your investigation, I'm trying to make sure the board doesn't swallow your
methods and conclusions along with the hook, line, and sinker. Obiwan's odds have no
bearing on TK being Zodiac.
"When you start stacking the odds, the number is no longer realistic, and (in my
opinion) one is
forced to accept that TK must have been The Z before FC."
I can only guess that you are so convinced that Ted Kaczynski was The Zodiac, you are
willing to accept anything as proof that he was. With methodology like this, it's
absolutely pointless to invest the time to fully analyze the proofs of things that are
unprovable. You have your views, I have mine. But I can't let 100% purified nonsense stand
unchallenged on here. Sorry, there just has to be a counter-opinion available on this.
Ray
| By Ray N (Ray_N) (user-38ldeuh.dialup.mindspring.com - 209.86.187.209) on Tuesday, July 23, 2002 - 05:21 pm: |
Sorry, please change "you have manufactured". I should have said, "Every occurrence has been manufactured."
| By Scott Bullock (Scott_Bullock) (spider-ntc-tb073.proxy.aol.com - 198.81.16.183) on Wednesday, July 24, 2002 - 12:02 pm: |
Ray,
You aren't expecting an actual key to the solution are you? I wouldn't abstain myself from
sex if such is the case, my friend.
Didn't Graysmith already "solve" the 340-character cipher back in '79? Let's see
here . . . ah, yes! Zodiac, p.243:
HERB CAEN:
I GIVE THEM HELL TOO.
BLAST THESE LIES. SLUETH
SHOELD [SHOULD] SEE A NAME
BELOW KILLEERS FILM. A PILLS
GAME. PARDON ME AGCEPT TO
BLAST NE [ME]. BULLSH*T.
THESE FOOLS SHALL MEET
KILLER. PLEAS ASK LUNBLAD.
SOEL [SOUL] AT H LSD UL
CLEAR LAKE. SO STARE
I EAT A PILL, A*SHOLE. I
PLANT MR. A. H. PHONE LAKE B.
ALL SSLAVES BECAUSE LSD
WILL STOLEN EITHER SLAVE
SHALL I HELL SLASH TOSCHI?
THE PIG STALLS DEALS OC [OF]
EIGHTH SOEL [SOUL] SLAIN.
Obiwan, would you be kind enough to run the numbers on Graysmith's conclusion with regard
to probability of random chance? In Graysmith's solution, he has Zodiac mentioning 2
different cops that worked the case, a plant on a phone at Lake Berryessa, Slaves, Souls,
a body count, etc. I'm just curious, what are the odds of Graysmith's conclusion being
random chance? Somehow I think it's going to be a little higher than TK being mentioned
twice.
Zander, if you were able to derive TK's name from the cipher you must obviously possess a
key of some kind, right? By all means, enlighten us as to the other parts of the cipher
that you've figured out. Or is that all you have; just the same name mentioned twice? If
so, that's pretty weak, especially in light of Graysmith's conclusion.
Scott
| By Peter H (Peter_H) (pool-141-154-20-140.bos.east.verizon.net - 141.154.20.140) on Wednesday, July 24, 2002 - 12:30 pm: |
Scott:
You already stated my position precisely: Occam's Razor. The simplest explanation of why
the cipher is not solved is that it can't be.
The rest of the discussion is beyond Greek to me.
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Wednesday, July 24, 2002 - 03:20 pm: |
Scott: 340-character cipher will .. never be solved because it was
never meant to be.
.
Ray: The last line of cipher text was only provided to fix the size ...that
much effort is being expended upon cipher text which is nothing more
than dead-end gibberish.
.
Peter H: The simplest explanation of why the cipher is not solved is that it can't be.
Dear Board,
I would like to clear up what appears to be a misunderstanding of
my recent post. The three comments above all refer to the
(interesting) topic of DECODING the cipher(s), to discern their
intended meaning. This is a difficult, but, certainly in the case of
the 480 cipher, worthwhile, endeavor.
However my recent posting has NOTHING to do with decoding the
meaning of the cipher(s), from unintelligible ciphertext into
readable plaintext. It is only about examining the actual
ciphertext, ie, those characters which the cipher author, who is
presumably the Zodiac killer, wrote. I do not assign any meaning to
those characters (ie T represents E, O represents S, etc.) The only
exception is that backward letters are read as their forward
counterpart, and circles count as O's., as described in my posting;
(see the link above) Otherwise, I read all the letters exactly as they
were written.
Perhaps, to avoid confusion, discussions of the SOLUTIONS of the
ciphers, (such as Graysmith's, posted above) should be held under a
different sublist of the Ciphers category, according to the
organization of this message board.
Therefore, Scott, I cannot "run the numbers" on Greysmith's solution,
because my analysis is only designed to see what the odds of a certain
pattern appearing IN THE CIPHERTEXT, by chance are. Which pattern
would you have me look for? What "matching criteria" should I apply?
I suspect you were requesting that I compute the odds that Greysmith's
mapping from ciphertext to plaintext should occur by chance? I do not
know how to compute such odds. That is why I do not venture to
evaluate any of the proposed cipher solutions as more viable than any
others, because I have no way of demonstrating such.
Obiwan
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Wednesday, July 24, 2002 - 03:28 pm: |
I'll bet the odds of Arthur Leigh Allen's name being found by random chance in the
340-character cipher are even greater than 100,000 to 20,000,000 to 1
I agree with you completely, Scott. The odds of such a name as Allen's, or Alfred E.
Newman's or Abraham Lincoln's appearing in, or as I say "closely matching" one
or two lines of the 340 cipher are very low. And indeed those names do not appear. (as far
as I am aware)
| By Ray N (Ray_N) (user-38ldehr.dialup.mindspring.com - 209.86.186.59) on Wednesday, July 24, 2002 - 07:19 pm: |
Zander wrote: "I allowed for the symbol on the last line that strongly resembles
a capital "I" to equal "I". Allowing each symbol to be its letter or
the one it closely matches: you get: THEODORVPLVVKIOLTGOD and KAZINSKIMDHNPO. That's the
standard by which I would set odds on, of course that is essentially what you have
done."
Obiwan:
The problem that appears here is that a statistical analysis was carried out showing a low
probability of TK's name appearing at random. The problem is not in understanding what you
have done. The problem is that, just like Allen, Neumann, Lincoln, etc, Kaczynski also
does not exist, except when the manipulation quoted above is first applied. Unfortunately,
Zander is attempting to use your results as a "proof of life" for his theory.
You are right though, this probably belongs on a different thread.
Ray
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Wednesday, July 24, 2002 - 08:33 pm: |
Ray N wrote: The problem is that, just like Allen, Neumann, Lincoln, etc, Kaczynski
also does not
exist, except when the manipulation quoted above is first applied.
In Fact, even after Zander's substitution of "Curvy I-with-dot" = "I",
KACZYNSKI does not exist in the last line of the 340 (its KAZYNSKI). However, even WITHOUT
Zander's substitution, a "close match" to KACZYNSKI can be found in the last
line, and a "close match" to THEODORE can be found in the first line. It is
these "close matches" which I was exploring in my analysis. Since the choice of
what is a "close match" and what isn't is arbitrary, I carefully define which
choices I'm using.
With a strict definition of "close match" (what I call Type 2), you are right,
Ray, that neither THEODORE nor KACZYNSKI exist on any single line of the code. It is also
true that under this definintion, as well as the more liberal Type 1 match definition,
ZODIAC does not exist in the 340 Ciphertext either. In order to find ZODIAC in the 340
cipher one needs to change a triangle to a D and change a K to a C. Given these two
changes are semi-arbitrary, should we conclude that the "near match" to ZODIAC
in the last line of the 340 cipher is just a case of finding a name we want to find out of
pure jibberish???
| By Scott Bullock (Scott_Bullock) (coral.tci.com - 198.178.8.81) on Wednesday, July 24, 2002 - 11:15 pm: |
Obiwan,
I understand what you are saying. However, please explain how finding "THEODOR"
and "KAZINSKI" in the 340-character cipher is not an example of "decoding
the meaning of the cipher(s), from unintelligible ciphertext into readable
plaintext"? After all, without manipulation of the characters/symbols, they are
clearly not examples of "plaintext." At least, not in the way in which I was
taught to read.
Scott
| By Douglas Oswell (Dowland) (147.philadelphia05rh.15.pa.dial-access.att.net - 12.90.24.147) on Thursday, July 25, 2002 - 12:55 am: |
Obiwan, correct me if I'm mistaken, but the point of this exercise isn't to decrypt the
cipher. Rather, we're assuming that a character like Zodiac might have gratified himself
by hiding his identity somewhere within the ciphertext, in a manner calculated to stroke
his own ego without actually giving himself away, or exposing him to risk if he were
caught. Given those conditions, there is always going to be a certain degree of
extrapolation to take into account, and the relative validity of any such exercise will
depend upon the amount of extrapolation that needs to be done. I believe you've taken that
into account. As the navigator of the B-52 said to Slim Pickens in Dr. Strangelove,
"I'm sorry, sir, but those are the numbers."
We now have four separate examples (3-Part Cipher, 13-Symbol Cipher, 340-Cipher and
"the Zodiac Speaking,") in which Kaczynski's name pops out with a relatively
minor bit of effort. That's significant.
| By Scott Bullock (Scott_Bullock) (spider-ntc-tc064.proxy.aol.com - 198.81.17.49) on Thursday, July 25, 2002 - 07:29 am: |
Doug wrote, "We now have four separate examples . . . in which Kaczynski's name
pops out with a relatively minor bit of effort. That's significant."
I can find Allen's last name in the first line of the 3-part cipher and it took me all of
9 seconds. However, admittedly, I had to use the half-shaded squares for the letter
"L." I figure that doesn't really matter though, after all, the half-shaded
square characters do represent the letter "L" part of the time in Don
Harden's solution to the first cipher, and they also appear side by side, just like the
double "L" in the word "Allen."
Hmm? How interesting. Allen's name is right there in the first 13 characters of the first
line of the first part of the first cipher. I wonder what the odds of that are?
Obiwan? Do you have enough data to compute the odds of that occurring by random chance?
Doug, do you find this observation significant? Seriously, tell me what you think, because
I don't think we are playing on a level ball field here.
Scott
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Thursday, July 25, 2002 - 08:41 am: |
Scott,
With regard to ALLEN in the 3-part cipher, I believe you pose a fair question for which
odds could be calculated, in priciple. I will not be able to do this calculation for
several days since I will be away & quite busy. However, it would help if you could
tell me:
1.) Which non-alphabet characters you would replace with alphabet characters in addition
to "half-shaded square" = "L"
2.) What are your "match criteria", ie how close do we have to come? Even after
we change "half shaded square" into "L", I do not see A, E or N in the
first 13 cipher-characters of the 3-part. Am I missing something?
3.) We need to know how many characters to draw at a time. You suggest ALLEN can be found
in the first 13 characters. If so we could draw 13 at a time from pool of 480.
Regarding your other question "please explain...":
The 1st line of the 340-cipher contains these letters: THER & backward D. If we were
decrypting the cipher, as Greysmith, Zander, Edward V. have done independantly (with
different results), then we would assign each of these letters of ciphertext to
represent a plaintext letter. Indeed we would to this for all the symbols in the
cipher to get a "solution".
On the otherhand what I have done is to only consider ciphertext symbols themselves. I do
not assume THER stand for other letters, I just keep them as they are. Now, in addition to
this I treat backward D as "D". I also treat the "O" like symbols as
O. I suspect this is where my effort looks like it trying to "decode" the
cipher. I admit, if you do not accept such replacements as plausable, (ie you prefer to
read ciphertext "Backward D" = nothing ) then you would not see a close
match to THEODORE in the first line, and the calculation I have done would not apply. (it
could be redone with a much looser definition of "close match" ) In that case
you would also not be able to find "ZODIAC" in the last line of the cipher.
May I ask: do you find a significant "close match" to ZODIAC in the last line of
the cipher? Or do you feel since 2 replacements need to be made, the apperent "close
match" to ZODIAC in the last line, is probably just a coincidence?
obiwan
ps. One last comment, which is an aside: I do not happen feel my latest calculation is
conclusive proof of anything, per se. It merely represents the first time a probability
has been able to be assigned to something related to the ciphers.
You will notice that I never stated "these must also be the odds of TK not being
Z". In particular, nothing I have done detracts from the large amount of evidence
which has been collected in regard to other suspects in this case.
Since I feel like I'm being dragged into a "my suspect vs. your suspect"
discussion, I will state the following. It is not the "goal" of my work to
"prove" that TK was the Zodiac. As Douglas knows, I approach this case from the
TK angle, with an interest in the socio-psychological ramifications it has on our modern
technological society, In particular how isolation and frustration can lead to varying
real and percieved political solutions, including, for example violence and non-violence.
So I would say that my angle on the case is to determine if the Z crimes were something TK
did in his early years. If I have an answer to that, yes or no, I'll be satisfied.
| By Lapumo (Lapumo) (p51-51.as1.clm.clonmel.eircom.net - 159.134.51.51) on Thursday, July 25, 2002 - 09:15 am: |
Here's another:-
In the first line of the 340 we have a close approximation to PETER O (PETRO) only one
letter missing.
In the last line of the first cipher we have
BEORITEMETHHPITI
Again we have PETER O, or let's take it a little further IM PETER O
Let's take him down to Riverside.Again depending on your interpretation, the letter was
signed ENTERPRISE (Peter Risen).
One could argue that these solutions are a little more concrete because there is a
connection.
Now I do not believe in the above, but I think it goes to demonstrate our problems with
the approach
on this thread.
I agree with you Doug,that the statement "this is the Zodiac speaking" is very
significant and I do also agree that finding Kaczynski's name or a close approximation in
there is interesting.But is that where it's significance lies?.I cannot argue with
Zander's math with regard to the last line of the first cipher. I do however,have major
problems with his interpretation.It's there though
and warrants a closer look.
The less said about his decipherment of the 340 the better.First of all it was based on
Graysmiths solution, which was "rubbished" in some detail by Glen.Not only did
Zander fall into the same trap as Graysmith by looking for things he wanted to find, but
took it a stage further
by attributing values to symbols, already suspect, in an attempt to force Kaczynski's name
in there.Of course this is just my opinion on the 340. However, all this is clearly solved
by sending it away for professional opinion.Then we can discuss what's there and what
isn't.Zander!
| By Howard Davis (Howard) (dsl-gte-10407-2.linkline.com - 64.30.209.40) on Thursday, July 25, 2002 - 11:06 am: |
Lampumo,
You had Allen in there too-according to old posts.
| By Zander Kite (Zk) (dialup-166.90.106.7.dial1.nashville1.level3.net - 166.90.106.7) on Thursday, July 25, 2002 - 12:46 pm: |
This whole thing is so simple and straightforward, it should be very easy to understand this. The last line of the 340-code contains the symbols K A Z I N S K(backward) and I(symbol closely resembling a capital I.) These symbols are a very unlikely combination because: K is used 4 times in 19 lines: A only 1 in 19: Z=4/19 i=7/19 N=2/19 S=3/19 I=2/19. Ray(and anyone else), I'd really like you to explain exactly how I am manipulating this. Zodiac is the one who chose which symbols to use in the last line, not me. As far as the symbol closely resembling a capital I, it does. Of course, if you are totally convinced that Arthur Leigh Allen was The Zodiac, then maybe it doesn't. Ray, let me ask you this: If I were to hand you a slip of paper reading: K A Z I N S K(backward) and the I symbol: what would you read: of course you(and anyone else) would read and pronounce Kazinski, so i can only infer that you don't accept that Kaczynski is communicated on the last line because you are resistant to this evidence, because it suggests that Kaczynski is The Zodiac and not Arthur Leigh Allen. Ray, unlike your December 18th phantom call, I have not manipulated or made up anything. You created a thread that named Allen as most likely The Zodiac because he was a white guy from Vallejo. That's an example of foundationless manipulation. I am working off what Zodiac has personally penned in on the last line. Theodor and Kazinski are communicated and matched to the first and last lines. It is clear to see it and very suspicious. I'm sorry, but the numbers don't lie. And it's done in the fashion that you'd expect from someone who has no interest in apprehension. He's not gonna lay out his whole name perfectly, yet when he picks up a paper and sees his name there, it is amusing and satisfying or whatever. The "C" is left out, but it is silent, so that's a good one to leave out. The "Y" is replaced by an "i" while the other "I" is not perfect.
| By Zander Kite (Zk) (dialup-166.90.106.7.dial1.nashville1.level3.net - 166.90.106.7) on Thursday, July 25, 2002 - 01:26 pm: |
Stats on my previous post should read K=7/19. Backward K=4/19. Lapumo, first of all, I am the professional opinion that you are looking for: but it's not necessary to realize that it's strange and well against the odds for Theodore Kaczynski to be communicated in the matched first and last lines. "Graysmiths" solution has no meaning here, because this is based on the undecoded symbols chosen by the one and only Zodiac. Because of the rarity of the symbols chosen within a 17 symbols line and the "last" match etc. for Kazinski, it defies millions to one odds.(my own math has it around 2.5 million to one). However, Theodor is not the same kind of odd-defyer. Similarly Petr O, is not a great one either. The "O" possibilities are way too much so 1/1 on that. The backwards "P" is also 1/1. The "E" and the "R" are rarer. Also you're dealing with a missing "E" that compromises the pronunciation a bit. I dont find "petro" as much of a longshot and I dont find it to have much meaning. I can't imagine, let's say a guy named Peter O'Baskins, picking up a newspaper and laughing about how he slipped "Petro" into the first line of the code.
| By Lapumo (Lapumo) (p51-148.as1.clm.clonmel.eircom.net - 159.134.51.148) on Friday, July 26, 2002 - 01:19 am: |
I clearly understand what your saying about the first and last lines.However any name
you can pick out of this cipher will produce the same odds against chance.We do not have
Peter O's last name,but that's not to say it (or a close approximation) is not in here
somewhere.If you choose to pick the first two lines instead of the first and last you can
also get Kevin O Dowd.You can pick Tom Reid from line eleven and Tom again from line 12.I
could go on with several names.
You make the point that finding a close approximation of TK's is interesting and it is.
However quoting odds has no meaning here unless there is a positive link.
There were over 2500 suspects in this case finding a name without proof that it was
intended
means nothing.
When I spoke of Kaczynski's name in the last line of the cipher I was referring to your
complete decipherment of the 340 code.I think you forced it in there.I believe you found
"THEO" in Graysmith's solution and went from there.
If your solution is valid,then you have one hell of a find.However the only way to verify
that is to send it away for independent analysis.It is after all, the
"professional" thing to do.
| By Scott Bullock (Scott_Bullock) (coral.tci.com - 198.178.8.81) on Friday, July 26, 2002 - 01:45 am: |
Obiwan,
Sorry, I accidentally led you astray. Allen's name doesn't appear in the first 13
characters of the first part of the cipher; it appears in the first 13 characters of the
first line of the third part of the cipher. Sorry about that. Nevertheless, the
odds of this appearing by random chance still have to be pretty far out there.
Lapumo wrote, "When I spoke of Kaczynski's name in the last line of the cipher I was
referring to (Zander's) complete decipherment of the 340 code."
Zander, you have a solution to the 340-character cipher? Would you mind sharing that with
us? Also, would you mind explaining why your solution is better rooted in the factual than
Graysmith's?
Scott
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Friday, July 26, 2002 - 04:27 am: |
Scott,
Zander's solution was posted on a different thread a few months ago:
http://www.zodiackiller.com/messageboard/messages/14/584.html?1013792066
Could I advise discussing it there?
ps. You can also find it, along with discussion of the 340 cipher here:
http://www.ciw.edu/chris/z/340explain.html
| By Ray N (Ray_N) (user-38ldcv6.dialup.mindspring.com - 209.86.179.230) on Friday, July 26, 2002 - 07:57 am: |
Zander:
You state that you are certain your find has merit. I think you are saying that in light
of Obiwan's information it proves Ted Kaczynski was the Zodiac. If I am correct on this,
what will you do with this information? What will be your next step?
| By Zander Kite (Zk) (dialup-65.58.109.164.dial1.nashville1.level3.net - 65.58.109.164) on Friday, July 26, 2002 - 08:56 am: |
Lapumo, Tom Reid is not the same thing as the Theodor Kazinski find. Theodor involves
7 out of 17 while Kazinski is 8 out of 17. That's a whole world of difference from 3 and
4. TOM only defies the odds of the T and the M being on the same line, because the O is
1/1. Finding Reid is probably about 1 in a 100, I'd guess. Kevin O'Dowd: you are combining
the first two lines: that's not the same thing at all. On some lines you will find combos
or names that are rare, but we see a pattern here of matching a first and last name to the
first and last lines: If someone notices a pattern of a similar 7 and 8 letter names
suspiciously matched or placed in the code: let me know: but I really can't accept smaller
names as a counter. It's not realistic to do so. If you keep doubling a penny: you will
have 32 cents, 5 days later, but you will be a millionaire before a month, is it? So odds
works the same way. The order of events was that I solved the 340 code in 1991. 2002: I
noticed for the first time that the code appears to hide "THEO" right before
"SEE A NAME"(I should have noticed that a long time ago, but I had it down as a
"should" misspelling). My secondary solutions for the 340-code are possibilities
only. I believe my original solution is mostly accurate. It seems as if you all like to
accuse me of somehow doctoring my results, but that's way off. No one knows how I came up
with my BEORIETE METHHPITI solution, for example, and maybe you don't wanna know.
Ray, I am only requesting and am interested in your opinion on this. You say that there
has to be a counter on this: and I want to know what it is. You have suggested
manipulation, without explaining further. There is only one letter in question, that is
the symbol looking like an "I"."KAZINS" are exactly the letter. And a
backward "K". Those are exact. "KAZINSK" and now place the capital I
symbol for "KAZINSKI". Or even with only the exact "KAZNSKI" it is
still suspicious. So really I was asking for further explanation on how you feel this is
manipulated. I am a believer in the reasonable doubt system. I believe that Kaczynski is
The Zodiac, the same way I believe that Ted Bundy was Seattles "Ted" killer. In
each case, there is not any evidence to convict.
| By Scott Bullock (Scott_Bullock) (spider-ntc-tb023.proxy.aol.com - 198.81.16.158) on Friday, July 26, 2002 - 08:56 am: |
Ray,
You've got it all wrong. In light of determining that the odds of a suspect's name
appearing in a line of non-ciphered text are so astronomical, I've decided that Allen must
be the Zodiac based upon the fact that his name -- correctly spelled, I might add --
appears in the first 13 characters of the first line of the third part of the first
cipher. Therefore, it can't be TK don't you see? Not only that, but his name also appears
in the 13 character, "My name is . . ." cipher: ART LEIGH ALLEN. My God man,
it's as plain as the nose on your face!
Personally, I don't plan on doing sh*t with my findings, for three reasons: The cops ain't
interested -- done tried that, I figured I'd bounce it about on the message board for 5 to
6 months to get an idea of what y'all think before actually acting on it, and finally,
because the fat, pathetic, lowlife, trailer trash, scumbag idiot is dead.
Okay Zander, I'm done harassing you, seriously. You seem like a bright guy and so does
Obiwan, so I won't waste any more of your time; at least, not on this thread. I'm just of
the opinion that the solution to this case does not exist within any of the cryptograms;
mainly -- though hyperbolic to be sure -- because of the reasons I've already outlined in
this thread.
Let's just say that I'm sticking to the right here and agreeing with Ockham's Razor: How
can any solution be deemed correct when it can be shown that other solutions exist? And I
am speaking to both ciphered and non-ciphered text. Besides, this type of crime
research and line of reasoning is much too esoteric for my tastes.
Scott
| By Scott Bullock (Scott_Bullock) (spider-ntc-tb023.proxy.aol.com - 198.81.16.158) on Friday, July 26, 2002 - 08:59 am: |
Wow, there you go, astronomical odds occurring right here in cyberspace! You must have known I was thinking about you!
| By Scott Bullock (Scott_Bullock) (spider-ntc-tb023.proxy.aol.com - 198.81.16.158) on Friday, July 26, 2002 - 09:13 am: |
Zander wrote:
"My secondary solutions for the 340-code are possibilities only. I believe my
original solution is mostly accurate."
"Ray, I am only requesting and am interested in your opinion on this. You say that
there has to be a counter on this: and I want to know what it is."
I wrote, "How can any solution be deemed correct when it can be shown that other
solutions exist? And I am speaking to both ciphered and non-ciphered text."
Where's the problem? I even gave you several examples of why your line of reasoning is off
without saying a word about manipulation. Are you choosing to ignore me, or eschewing the
truths of which I speak?
| By Scott Bullock (Scott_Bullock) (spider-ntc-tb023.proxy.aol.com - 198.81.16.158) on Friday, July 26, 2002 - 09:16 am: |
Ps. Okay, now I'm done harassing you.
| By Zander Kite (Zk) (dialup-65.58.109.164.dial1.nashville1.level3.net - 65.58.109.164) on Friday, July 26, 2002 - 09:20 am: |
Hi Scott. Look at those odds! I thought of a good example for Ray concerning his argument "if it's not good enough for the courts, then it's not really evidence." Imagine if the last line of the 3 part cipher read: CTVJWTNGKIJCNNGPX. Now if that was the case(those letters are all 2 up from ARTHURLEIGHALLEN(X)), I would agree that Allen must have been The Zodiac. But, it's something I wouldn't bring to court.
| By Lapumo (Lapumo) (p50-49.as1.clm.clonmel.eircom.net - 159.134.50.49) on Friday, July 26, 2002 - 10:08 am: |
"Tom Reid is not the same thing as the TK find".
No Zander it is not.What it is though,is relative.
It depends what you are looking for.A name is a name.Doesn't matter whether Kacyznski's
name is longer and it doesn't matter how many letters are in the name.I am not approaching
this because I want to knock Kaczynski.I believe more than anything else that Zodiac's
name is in here somewhere.If TK is Zodiac so be it.However calling odds on close
approximations does not advance this case anywhere.
When the correct name is found,it will be shown that it was intended, there will be a
pointer to where to look,there will be instruction on how to decode it and when it is
decoded, proof that we have arrived at the correct answer will be provided.That and only
that is what's going to set it apart from everything else.
| By Ray N (Ray_N) (user-38ldcv6.dialup.mindspring.com - 209.86.179.230) on Friday, July 26, 2002 - 10:21 am: |
Zander,
That's a fair question. My counter opinion is that you haven't found anything, but rather
willed it into being. Here is the manipulation I am talking about. Really, a better word
for it might be BIAS. In other words, we don't really have a true anagram on TK's name
here. What we have is a set of 34 letterform symbols from which you have selected those
which make up a close variant of TK. A true anagram would be something like this:
YNANXRIO = RAY NIXON
All letters of a typical anagram must be used for the solution to be valid. Alternately,
if these letters were "buried" in a larger document, there would have to be some
predescribed algorithm provided by the crptographer to enable the cracker to pick out only
the relevant letters. Certainly such an algorithm might be cryptic, but in order to have a
credible solution, the burden is on you to indentify and prove it. What you have done is
akin to the following:
Whomever's name is in this cipher wins $1 million dollars:
ANKBSRXYNVPQZ
Obviously, since I want the money, I'll pick only the following: QANRXYN, which gives RAY NXQN. I'm not going to worry about the Q because it looks like an
O nor am I going to be concerned about the symbols I didn't use. Just give me the money.
What's worse, in your 340 find, it happens not after the plain text has been deciphered,
but you are applying this to the raw ciphertext, which can easily be argued to have no
legitimate meaning on it's own (unless you can find some proof). You ignored many of the
symbols on those lines subjectively, as if the rest had no intended meaning, yet you offer
no method by which a codebreaker is supposed to be able to pick them out. As far as the
numbers go, again, you might find them interesting. But Obiwan's numbers are not
applicable to what you have done.
You have, in the opinion of the vast majority on here, not achieved a valid solution. If
you are that impressed with them, I'll repeat Lapumo's suggestion to have them subjected
to a professional cryptographic examination. That is where the rubber will meet the road,
not on this message board. The "nonsense" I was referring to was your assertion
that this find proves TK was the Zodiac. I do maintain that your find is interesting, but
not any more than any other name that might be found by a similar, subjective method. Of
course, my fault-finding doesn't necessarily mean that TK was not the Zodiac. It only is
intended to say you haven't proved that he is. If you don't claim you have, I have no
problem with your posts here, and withdraw my "nonsense" label with apologies.
The problem with your 340 solution is that it is based upon RG's solution. I know you
think it is correct. Graysmith thinks his is correct. See how it works? Everybody thinks
theirs is correct. The major problem with Graysmith's solution is that he got started on
it with a set of his infamously unfounded assumptions of fact, namely that Zodiac was
fixated on Herb Caen and was a drug crazed lunatic. Thus the solution is based on certain
important letters contained in HERB CAEN, PILL, PILLS, LSD. If he is not correct on these,
the whole solution is off. He relies again on the drug stupor angle to explain the
incoherency of his solution. He may be right, or you may be right. Both remain highly
suspect.
I am in complete agreement that this case might indeed be eventually solved by
cryptography. What we (and the authorities in particular) are going to be looking for,
however, is a system by which someone is going to find the name of the Zodic by applying a
legitimate, coherent, describable methodology and be able to prove it correct beyond a
reasonable doubt.
Ray
| By Scott Bullock (Scott_Bullock) (spider-ntc-tb033.proxy.aol.com - 198.81.16.163) on Friday, July 26, 2002 - 10:45 am: |
Ray wrote:
"I am in complete agreement that this case might indeed be eventually solved by
cryptography. What we . . . are going to be looking for, however, is a system by which
someone is going to find the name of the Zodiac by applying a legitimate, coherent,
describable methodology and be able to prove it correct beyond a reasonable doubt."
That's exactly what it will take for me to give a solution to the 340-character cipher any
legitimacy. However, if the same conclusion cannot be achieved time and again using blind
experimentation, I'll happily relegate any conclusion to the rubbish heap where it
belongs. That's an extremely tall order my friends, but I wish you luck nevertheless.
Scott
| By Zander Kite (Zk) (dialup-65.58.111.16.dial1.nashville1.level3.net - 65.58.111.16) on Friday, July 26, 2002 - 02:06 pm: |
"Graysmiths" solution has been approved by code experts as legit. My
solution is essentially the same as "Graysmiths" anyway. I've pointed out a few
additional items like "THEO" right before "SEE A NAME" but
"Graysmith" has the same thing also, just that he accepts it as errors on
"SHOULD". Also i've explained the long nonsense sequence placed in the middle as
an attempt to confuse by running back nearly the same letters as before it. Also, I've
showed how when Zodiac decides to use the real first letter of a word, his second choice
is always the second or last letter of the word, suggesting design.
I would use the odds defied as a guide, and not say "well, TK must be The Zodiac by
2.5 million to 1 odds." It's when you start stacking the odds though, that you are
facing long odds that Kaczynski is not The Zodiac. Honestly, in my opinion, I feel there
is a lot of flawed logic being displayed here by several people, and I don't want to
counter every little bit. Let me put it this way: I find it highly, highly suspicious that
disaffected bomber, killer, and letter-writing publicity-seeking Theodore Kaczynskis name
is communicated in the 340-code, the way that it is. We are only dealing with letters of
the alphabet, it's not complicated, and really doesn't require much analysis. So, at this
point, either one is moved by this or not, I guess. I wonder though, if we were to find
out tomorrow, that there was a DNA match to Kaczynski, if the people that think there is
nothing to this, would still think that?
| By Douglas Oswell (Dowland) (79.philadelphia04rh.16.pa.dial-access.att.net - 12.90.23.79) on Friday, July 26, 2002 - 04:39 pm: |
Remember, too, Zander, that when you say "disaffected bomber, killer, and letter-writing publicity-seeking" you're only looking at the tip of the iceberg. Your point is well taken. This isn't Joe Blow whose name is popping up all over the place with just a minimum of effort.
| By Douglas Oswell (Dowland) (79.philadelphia04rh.16.pa.dial-access.att.net - 12.90.23.79) on Friday, July 26, 2002 - 04:41 pm: |
Just as an aside, I'm gratified to see that someone is using the term "disaffected" that I've coined to describe what is essentially the mass-murder type. I think it states the case more accurately than a term that simply defines the number of victims taken over a specific period of time.
| By Howard Davis (Howard) (ont-cvx1-85.linkline.com - 64.30.217.85) on Friday, July 26, 2002 - 11:58 pm: |
The two cryptologists that are listed as approving GSs 340 code work are Greg Mellon
of the American Cryptogram Association.Internet searches show the late Mr. Mellon had a
good code background.Eugene Waltz of the same association agreed with Mellon.GS is
supposed to have a letter from Mellon (and Waltz)congratulating him "...on having
broken the second Zodiac cipher.Both Zodiac messages are homophonic ciphers with the
second complicated by an added,apparently random,transposition of the letters of each
word...The errors in spelling and in encipherment are to be expected and are within an
acceptable range...you have extracted all the information that is there.
Waltz wrote"...we[Mellon]are both agreed that your solution is good and valid...You
are to be congratulated...for breaking the cipher..."
| By Scott Bullock (Scott_Bullock) (coral.tci.com - 198.178.8.81) on Saturday, July 27, 2002 - 12:29 am: |
Interesting stuff. If Graysmith's conclusion to the 340-character cipher has been
corroborated by 2 experts in cryptography (I wonder, were the results corroborated
blindly, or did they merely "check" Graysmith's work/conclusion for viability?),
then why are people still trying to decipher it? Tom has the code listed as
"unsolved" on this website; Zander has come to a conclusion that is close too
but not exactly the same as Graysmith's; Eduard's solution is altogether different; and
others believe -- such as myself -- that it hasn't been solved at all. What's up with
that?
As I stated in an earlier post, if the cipher can be solved time and again with the same
results, then said solution must be correct. If not, or if multiple solutions can
be ascertained, then I believe that no true solution exists. Furthermore, I bet that the
scientific community would concur with this assessment.
Thoughts?
Scott
| By Scott Bullock (Scott_Bullock) (spider-ntc-td043.proxy.aol.com - 198.81.17.168) on Sunday, July 28, 2002 - 12:37 am: |
I can only assume from the lack of response either one of two things: Either nobody has been able to corroborate their findings utilizing blind analysis, or someone has done so and just doesn't wish to share the information at this point in time. Okay, that's fine with me. I'm still left waiting either way.
| By Lapumo (Lapumo) (p50-26.as1.clm.clonmel.eircom.net - 159.134.50.26) on Sunday, July 28, 2002 - 10:18 am: |
Zander,
Its not that I think there is "nothing to it"
I do find it interesting.I believe Zodiac's identity is in here somewhere.Hence when we
find kaczynski's name or a close approximation more than once its time to sit up and take
a look.
Each find must be looked at individually and the merits of each examined.If you are the
professional you claim to be ,then you know full well, that these cannot be
"lumped" together for statistical analysis.
What is crucial here is how these "finds" have been arrived at.
You have explained how you arrived at the solution at the bottom line of the first
cipher.It's there,the math is good.Its interesting and merits a closer look.The flip side
of the coin is that you have made assumptions
(not that I'm saying the are incorrect)you have assumed that there are 17 letters as
opposed to 18.You have linked it to the crossed circle as laid out in the phillips
map.This is something Zodiac was using for another purpose.Furthermore,your solution
depends on extracting random letters from the last line.Again ,let me say you could be
100% correct.However if there is any flaw in your methodology the solution is meaningless.
That there is a close approximation of Ted's name in the introduction "this is the
Zodiac speaking" and in first and last lines of the 340 ,which are also
interesting.And yes,if the DNA comes back positive in favour of Kaczynski,I for one would
inclined to go with what you are suggesting.However,again this all hinges on the name
"THE ZODIAC".He either chose this mokiner because he could work it around his
real name(there's a reasonable argument for that) or it holds some other significance for
him.If its the latter, then again, approximate solutions are meaningless.
Lastly your most substantial work comes from the complete decipherment of the 340
cipher.You have the opportunity Zander,to do this investigation,the people on the board
and yourself a great service by simply sending this away for independent analysis.With
respect,its no good quoting Graysmith here.Even if it has been verified by some
experts,then others have rubbished it.The general consensus is that this decipherment is
flawed at best.The difference it makes now is that we have Kaczynski's name or we do
not.We can then go on to discuss this significant find or waste out time discussing a
whole lot of nothing.
| By Zander Kite (Zk) (dialup-65.58.110.13.dial1.nashville1.level3.net - 65.58.110.13) on Sunday, July 28, 2002 - 11:05 am: |
Scott, I agree with you on that. I have reached basically, the same results as "Graysmith", more or less on my own. The reason that code experts have approved the "Graysmith" solution, is that it has to be, by and large, correct. That's the reality of codes, you can't just make up what you want or the rest is dribble. There are disputable areas involving encirclement etc.. For example, the colored "P" is used only twice, both for the word "Pills", so maybe the colored P doesn't equal "L", maybe it's not "pills". But, for example, there is no doubt that the Zodiac opened with "I give them hell too". Other areas are too clear to be in question like "These fools shall meet killer". The Zodiac must have wrote in code, at least most of the "Graysmith" solution. Perhaps there are some corrections to be made, or secondary or otherwise hidden messages. Code experts and I and "Graysmith" have agreed that one of the sections reads "LUEHSTHEOLHSSEEANAME." I propose it is to be read "LUEHS THEO LHS SEE A NAME". No need for a further "professional" opinion, it's already been approved. Another area I encircle different than "Graysmith" is where he has "Phone Lake B.. All slaves.. I have "Phone Lake B slllaavees". I believe that that is written because Hartnell offered The Zodiac his phone number. I find a later Unabomber false clue reading "Call Nathan R. Wed 7 P.M" to be suspiciously parallelled to the Lake Bery. event.
| By Ray N (Ray_N) (user-38ldeek.dialup.mindspring.com - 209.86.185.212) on Sunday, July 28, 2002 - 11:31 am: |
Has there every been any interest in exploring whether Z might have used more than one key sheet for this cipher, that different sections might have been encoded using different key sheets? Or the alternate possiblility that on different lines, Z employed a shift of some sort on a single key sheet to shift the substitution letters? If a pattern could be identified as to the nature of the key shift, one unified, comprehesible message might be deciphered. Hmmm...I wonder....
| By Zander Kite (Zk) (dialup-166.90.104.178.dial1.nashville1.level3.net - 166.90.104.178) on Sunday, July 28, 2002 - 12:08 pm: |
There is one long nonsense sequence in the middle of the 340. I believe it is an
attempt to confuse by running back the same letters, but it could involve a seperate key
or some trick.
Lapumo, like Howard says, several code experts approved the "Graysmith"
solution. My solution doesn't stray too far from "Graysmiths", so similarly it
has, more or less, been verified. So, it's already been done and is now up to the
individual to accept it or not. But, I know I wouldn't bust into a brain surgery operation
and tell the doctors to let me operate.
I will accept the position that it is only coincidence as far as my Beoriete Methhpiti
solution, because it may well be. It was the first and only number system I tried, besides
basically gauging stats on the letters. Actually, I was looking thru the back of yellow
Zodiac, and noticed the part about looking for an encoding wheel as a possession for The
Zodiac. That made me think of the Zodiac symbol as a circle. I originally was going to use
3,6,9,12 like a clock, because I was thinking circles and numbers. Then I remembered Z
used that in a letter, looked it up to verify, and discovered it was 0,3,6,9.
Instinctively, I realized it would be a tough fit, so i was surprised to find that it
worked out. But I was shocked to see that the double letters(EOK) all equalled the same
letter. The designed appearance of the string of numbers and the zero beginning and end
made it more compelling. The Zodiac may have had an obsession with time. It could be a
coincidence, but I proudly proclaim it as the best "Beoriete Methhpiti" solution
out there.
| By Scott Bullock (Scott_Bullock) (spider-ntc-tc074.proxy.aol.com - 198.81.17.54) on Monday, July 29, 2002 - 10:30 am: |
Zander, I understand exactly what you are saying and, if blind analysis can prove the same solution time and again, then I'll have to admit that the 340-charater cipher is, indeed, solved. Under those conditions, there simply cannot be an argument to the contrary. What I'm wondering is if you have submitted your work to such an analysis? If not, then talking about it doesn't carry much weight. And I agree with Lapumo and Ray than comparison to Graysmith's solution is tenuous at best for the same reason: Was it or was it not subjugated to blind analysis? The answer to that question makes all the difference in the world if you want an investigator to take your work seriously. You understand what I'm saying, right?
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Tuesday, July 30, 2002 - 07:39 pm: |
How can any solution be deemed correct when it can be shown that other solutions
exist?
Scott, I would say it can't. However do you think the 3 part cipher has been solved? I bet
you do, and the reason you think so is that the standard solution returns readable text
without anagramming, etc. I could easily come up with a Graysmith-340-esque solution for
the 3-part cipher, requiring anagramming, etc, yielding garbled text, which you
would rightfully dismiss out of hand on the basis of Occam's Razor. This is why I consider
the 340 cipher "not solved", in spite of useful "candidate" solutions.
Also, I place very little weight on the experts who "verified" Greysmith's
solution. We can apply Occam's Razor just as well as they can. I'm sure they just checked
it and did not try to derive their own solution.
I would bet 100 zodiac buttons that NO TRUELY INDEPENDENT confirmation of Greysmith's
solution has ever occured. Neither I nor Zander could do this because we have both seen
the Greysmith solution. I propose that we all try to find crypto-knowledgeable people who
have NOT seen Greysmith's solution and see what they can get out of it. My guess is they
will come to the same conclusion the NSF or FBI or somebody came to: there are too many
different characters for this length of code to get a
definitive solution from pure cryptology. Having said that, it is conceivable that Zodiac
made the code unsolvable & unproveable via cryptology BUT solvable IF you knew
something about him, for example his identity, his background, etc.
P.S. Scott, since you are done harrassing, perhaps I may be permitted to
"harrass" you? Would you care to answer my previous question:
Do you find a significant "close match" to ZODIAC in the last line of the
340-cipher? Or do you feel that since 2 replacements need to be made, the apperent
"close match" to ZODIAC in the last line, is probably just a coincidence?
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Tuesday, July 30, 2002 - 08:02 pm: |
if multiple solutions can be ascertained, then I believe that no true solution
exists.
I agree Scott. I would say that several candidate solutions exist, none confirmed.
Confirmation would have to take place via means other than cryptography, or else by an
exhaustive exploration of ALL POSSIBLE solutions, which as I easily computed is beyond the
scope of all computers in the world now.
Regarding your questions to Zander on independant analysis: YES I have tried to
independantly derive A solution to the 340 code, completely disregarding the Greysmith
solution. I wrote a computer program similar to the one posted by Bobbitt to assist me. I
could not come up with anything that really made sense, although there are still a lot of
possibilities to be explored.
| By Scott Bullock (Scott_Bullock) (spider-tm022.proxy.aol.com - 152.163.197.52) on Wednesday, July 31, 2002 - 10:07 am: |
Obiwan, you asked, "[D]o you think the 3 part cipher has been solved?"
Of course I do, don't you? It was solved into readable text and is the only solution that
will ever exist. That is not the case with the 340-character cipher, at least, not
in my opinion.
"I could easily come up with a Graysmith-340-esque solution for the 3-part cipher,
requiring anagramming, etc, yielding garbled text, which you would rightfully dismiss out
of hand on the basis of Occam's Razor."
I'm not real sure I understand what you mean, but I'll give it a shot. First of all, what
the hell is "a Graysmith-340-esque solution for the 3-part cipher" suppose to
mean, and why in the world would you want to do that?
Here's the difference, in my opinion: For a cryptogram to be truly solved it must have one
and only one readable text that can be blindly analyzed at will and the exact
same solution will be derived time and again. On the other hand, anagramming
non-deciphered text is the equivalent, at the very minimum, of rolling 340, 36-sided [A -
Z & 0 - 9) dice onto a table and then looking at them to see if anything interesting
strikes your fancy. You could literally roll the dice until you were, at some point in
history, able to read whatever it is that you desired. Therefore, and in other words, how
can there possibly be "one and only one" solution to the garbled text?
As for the 340-character cipher, I agree that it is not solved. I was merely alluding to
the fact that Graysmith's solution must be included among the "candidates" of possible
solutions. You see, that's the part that kills me, the idea of multiple
solutions is absolutely absurd, and can only serve to show that no solution actually
exists.
"[I]t is conceivable that Zodiac made the code unsolvable & unproveable via
cryptology BUT solvable IF you knew something about him, for example his identity, his
background, etc."
Or his name, right? How is that anymore objective than not being able to solve the
340-character cipher because you and Zander "have both seen the Greysmith
solution"? Furthermore, how is your solution any more significant than the one I
found in the 3-part cipher that "implicated" Allen? After all, I found it in
non-deciphered, garbled text and had to use anagramming for 2 of the letters, which were
actually the same "character" -- the letter "L" -- in both the
deciphered text and in the non-deciphered text. What are the odds of that? Astronomical?
"Do you find a significant 'close match' to ZODIAC in the last line of the
340-cipher?"
Yes, I find a "close match" but I do not consider it significant. Not at this
point, anyway.
Scott
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Thursday, August 01, 2002 - 04:52 pm: |
Scott, my question about the 3 Part cipher was just intended to point out that you,
and all of us, have applied some criteria to candidate solutions before judging them as
"acceptable". Whatever criteria you apply to the 3 part (and you layed out
yours) we could also apply to the 340. That's all.
"how is your solution any more
significant than the one I found in the 3-part cipher "
Let me clarify that I don't have a solution to the 340 cipher. I only use the word
SOLUTION to discribe translating ciphertext into cleartext.
Now there is in fact a difference between the finding of ALLEN in 3 part and the finding
of THEODORE & KAZNSI in the 340. The difference is that in the 340 we are working with
the cipher text. The encoder of any message has complete freedom in which characters to
use for cipher text. Therefore the ciphertext can easily be made to contain letters or
words separate from the plaintext for which it stands. In the case of searching for a name
in the plaintext, there is much less freedom because the author has presumably already
come up with an intended messages (about slave in the afterlife, etc.) . So there is a
difference here. Having said that, I still think it would be possible to compute the odds
regarding ALLEN as you suggest, I just am not able to do this right away.
| By Scott Bullock (Scott_Bullock) (coral.tci.com - 198.178.8.81) on Friday, August 02, 2002 - 03:44 am: |
Obiwan, you wrote, "Now there is in fact a difference between the finding of
ALLEN in 3 part and the finding of THEODORE & KAZNSI in the 340. The difference is
that in the 340 we are working with the cipher text."
Obiwan, that is exactly what I am working with also: the ciphered text of the 3-part
cryptogram.
Scott
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Friday, August 02, 2002 - 01:30 pm: |
Scott: Correction to my previous: In order to find "ALLEN" in the 1st line
of the 2nd part of the 3 part cipher we must use 3 letters from Cipher text (AE & N)
and 2 letters from plain text "LL". To find this 5 character match on a single
line, we were able to draw from 34 possible characters of plain and encypherd text.
You seem saying that the ****CIPHERTEXT***** "Square with a Diagonal Line through it
with the lower half filled in" looks unmistakably like a ciphertext "L" to
you, right? I do not see any reason for making this assignment. Although we could make
some more obvious assignements in the ciphertext of this line, like "Backward C"
= C, or Even "O" with line = "O". These seem relatively
straightforward CIPHERTEXT replacements. But replacing fully or half filled squares with
english letters does not seem so obvious to me since there is no English letter which
looks like a square box. Yes, T, L, I & H all have right angles, but none of them
obviously looks like a box to me.
Let me put this another way. If we are to compare the 3-part and the 340 ciphers on the
same footing for purposes of my calculation, then we must treat them the same. That is to
say we must treat them as UNSOLVED. You and I agree that the 340 is unsolved. In order to
compare Ciphertext with ciphertext, we must forget that we know the solution to the 3
part, and only look at the ciphertext. When we do this we only have a 3 Letter AEN close
match to ALLEN. Now, if you find such a match significant then yes I could calculate the
odds of drawing 17 cipher characters at random and achieving a near match (by this
definition) to ALLEN.
| By Lapumo (Lapumo) (p51-248.as1.clm.clonmel.eircom.net - 159.134.51.248) on Saturday, August 03, 2002 - 06:22 am: |
Zander,
Did you ever try the method you applied to the last line cipher, on the Bomb code?.
Seems a very reasonable possibility in those circumstances!
| By Scott Bullock (Scott_Bullock) (cache-mtc-ak04.proxy.aol.com - 64.12.96.201) on Saturday, August 03, 2002 - 12:27 pm: |
"You seem saying that the ****CIPHERTEXT***** 'Square with a Diagonal Line through
it with the lower half filled in' looks unmistakably like a ciphertext 'L' to you, right?
I do not see any reason for making this assignment."
Despite the fact that it is the exact same character in the same line that the rest of the
ciphered text is in? Despite the fact that it appears in said line twice, side-by-side,
and represents the same letter in the ciphered text as it does in the deciphered text,
which is also side-by-side? I suppose the frequency of such an occurrence is one in three,
eh?
Zander's find is interesting, I'll admit, but it is way too subjective to be taken
seriously. If not, then I can apply my "Allen in the 3-part cipher" with the
exact same vigor. Either way, the odds are still astronomical. Why focus on the esoteric
view when the realistic is still undecided?
Scott
| By Douglas Oswell (Dowland) (171.philadelphia01rh.15.pa.dial-access.att.net - 12.90.16.171) on Saturday, August 03, 2002 - 02:03 pm: |
A .22 and a howitzer both work on the same principle, and both fire a projectile. The difference is that the .22 fires a teeny little projectile and the howitzer fires a great big projectile.
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Saturday, August 03, 2002 - 02:41 pm: |
Scott I'm afraid I don't understand this sentance:
"Despite the fact that it is the exact same character in the same line that the
rest of the ciphered text is in? "
Despite the fact that it appears in said line twice, side-by-side
The fact that "Lower-Half-filled-square" appears doubled in ciphertext does not
suggest to me that as a CIPHERTEXT character this should be taken to be "L". It
does not look like L, any more than say "N". However the doubling does suggest
that if we are trying to SOLVE the cipher, as the two amatures did, then we would be wise
to consider doubled CIPHERTEXT characters as "L"'s, since L is a frequently
doubled letter. I am not, repeat not talking about solving ciphers here.
But as I said, when computing odds of CIPHERTEXT, we must ignore any solutions we think we
have as to the plaintext. Otherwise we are comparing apples and oranges and calculation
must account for both cipher and plain text and thus becomes vastly more complex.
obiwan
| By Zander Kite (Zk) (dialup-65.58.111.48.dial1.nashville1.level3.net - 65.58.111.48) on Saturday, August 03, 2002 - 09:55 pm: |
Scott Bullock: There's a reason I can pull in about $4000 a year at a dog track thru
handicapping. It's because I understand "odds" and because I'm competing for the
money with people like you at the track. I'm sorry but I just can't accept finding
"Allen" like you have in the first line of the third part of the 3-part cipher.
It's woefully pathetic, and reflects odds-ignorance. In fact, I'll give you a good
odds-estimate on that right now. The "L" is very common in the 3 part code. So
both "L's" defy no odds at all, they are 1 to 1. Which leaves us with finding AE
and N within either the symbols or decoded symbols. At this point, it should already be
abandoned as meaningless because AEN are such common letters, since you've made it
available to pick from either symbols or decoded symbols. Just to really make this easy to
understand: Look at it this way: You say the odds are astronomical of finding
"ALLEN" in the fashion you have, on the first line of the third part. However
out of 24 lines, "ALLEN" can be found that way in 9 of 24. When someone signs
something, it's usually at the end. In summary, I find this comparison to Kazinski as
insulting. There are several strong examples on the table for Kaczynskis name being
slipped into his codes and writings. Arthur Leigh Allen is nowhere to be found, and he is
portrayed as this great risk-taker and police-taunter, so I'd expect his name to be seen
somewhere suspiciously, but it's not!
Lapumo, I'm not quite ready to reveal my 32-code solution, and to be quite honest, I don't
think that you all are ready to hear it.
| By Lapumo (Lapumo) (p50-14.as1.clm.clonmel.eircom.net - 159.134.50.14) on Sunday, August 04, 2002 - 09:59 am: |
Zander,
Yet another brilliant one liner "I don't think that you are all ready to hear
it".It's right up there with such gems as "I intend to lay to waste any 340
analysis previously posted" and "the solution is correct","if you
reject my solution I would strongly advise against gambling as a career move" (Scott
be warned).
Like everybody else Zander ,when you present "evidence" here on the board,it's
going to be analyzed,discussed and challenged.
You appear to want us all to sit back and accept what you put forward.When you are
challenged, you retreat back into your shell and cry foul!
Of course you had the opportunity to "prove" your statements correct by sending
it away for independent analysis,you declined.
Now,when asked another honest question,"we are not ready to hear it".If the same
technique that you used on the last line of the first cipher was applied to the bomb code
and found to work,then it could only serve to strengthen your earlier finding.Would it
not?
| By Scott Bullock (Scott_Bullock) (cache-dr05.proxy.aol.com - 205.188.209.169) on Monday, August 05, 2002 - 01:53 pm: |
Zander wrote, "The "L" is very common in the 3 part code. So both
"L's" defy no odds at all, they are 1 to 1."
When they appear side-by-side in the same line of text as the "A" the
"E" and the "N", and are also representative of the letter
"L" in the deciphered text, the odds are not one to one, they are much greater.
Maybe the odds are not "astronomical," but they are certainly greater than 1 to
1. Even appearing side-by-side in the text makes the odds greater than 1/1. Take a look at
this very post for example. How many letter "Ls" do you see? How many of them
appear side-by-side? I count 17 letter "Ls" but only in one instance are they
side-by-side. See how easy that was to debunk your assertions about odds? Where did you
come up with that 1 to 1 crap?
| By Zander Kite (Zk) (dialup-166.90.117.25.dial1.nashville1.level3.net - 166.90.117.25) on Monday, August 05, 2002 - 03:12 pm: |
A count of the "L's": 31 in real letters: which on it's own means you'll find 1.3 L's per line(31/24lines): But also you've included "L" symbols. Your "Allen" find requires located two "L's" in the same line. It is basically 1 to 1. If you are counting backwards "L's" included then it is 1 to 1(in other words, it reaches or passes a 48 count). Either way, it just is not a factor. In laymans terms(even though it already is), the "L's" are too common in this code, for finding 2 "L's" in a line to have any meaning at all. If you say you will draw two aces out of a deck and then do so, you have defied 221 to 1 odds. The odds of the first ace are 13 to 1, while the second ace is 17 to 1(51 cards left, 3 aces left). 13x17=221. But, if you only say you will draw 2 of the same card, you are only defying 17 to 1 odds. Because it doesn't matter what the first card you draw is, you only have to match the second card to it. That first card drawn is meaningless, a non-factor, it's 1 to 1. The "L's" are the same thing in the code, they are meaningless in affecting the odds. Scott, I really don't know where you're going with this double "L" idea. You seem to be suggesting that The Zodiac used words like kill, will and thrilling, as an attempt to clue us in that his last name also included a double "L" in it. That's kind of ridiculous to me. I shall no longer counter any counter to "Theodor Kaczynski", if it is ridiculous like this or if someone tells me they can also find Don Ho or Ed Ott in the code, and a name is a name so it doesn't matter. I would rather hear "Well, Athur Allen must have been The Zodiac, so there can't be anything to this". That would work for me, this other nonsense is just insulting really. I also have additional analysis to offer, but one would have to accept the "Graysmith" solution. In the solution, all the vowel symbols equal themselves. It's a pattern. A=A E=E ETC. The symbol "A" is used only one time before the last line (the "A" in Kaz(I)nski). But we all know that the "A" is very commonly used in words, so this makes it look more suspicious. Another possibility is that it was meant to be read "Ted Kaznski".
| By Howard Davis (Howard) (66.59.238.81.lcinet.net - 66.59.238.81) on Monday, August 05, 2002 - 10:41 pm: |
In Kellehers This is the Zodiac speaking, he gives another encipherment for the 340
"Theifs slowed deaths from...Death off as still forrest...eat from...With tests...it
is ears Made the forrest far...A theif of...so Later...while...were Was a
foot...Zodiac."
He does not inform us who did the 'translation',but it is included in this thread as
another attempt at deciphering the 340.FYI
| By Scott Bullock (Scott_Bullock) (cache-mtc-ak04.proxy.aol.com - 64.12.96.201) on Wednesday, August 07, 2002 - 09:52 am: |
Zander,
If you are going to try and discredit me, at least do it correctly. From the outset I
stated that I was only concerning myself with just one block of the 3-part cipher.
Remember one other thing, I, like you and Obiwan, am strictly dealing with, for the
moment, ciphered text. If you look at this one block of ciphered text you will
notice the following on the first line: "N", backward "K",
"O" with a horizontal slash through it, "S", backward "C",
"E", "/", "Triangle", "Square" partially shaded,
"Square" partially shaded, "Z", backward "F", "A":
Okay, hold it right there for a moment. Examine the line to that point. There are 13
characters, right? However, if you observe closely, you should also notice something odd.
Do you see it? I do, it's Allen's last name spelled too the letter and in perfect
order; reading from right to left.
But wait, you ask, where are the two "Ls" that are in Allen's last name? Good
question; one that I thought about myself. Then I thought, wait a minute, the
"Ls" are right there in the cipher; in the exact same block of 136 characters of
ciphered text: Two "Ls" which are, curiously, the only two "Ls"
in the entire 136 character block. I figured that such a find must be significant
so I placed them among the original 13 characters to equal 15 so that I could derive
"Allen" from the block of ciphered text. Oddly, when I went to the deciphered
text to determine what the two partially shaded "Squares" and the two
"Ls" represented in the decoded text, it turned out that the "Squares"
were "Ls" after all, and the two "Ls" represented
"Ts."
Pretty bizarre, huh? Now, I'm not sure what the odds of my "find" are, but it
sure as hell has to be a lot larger than 1 to 1, wouldn't you say? First of all, there are
only 2 "Ls" in the 136 character block of ciphered text to which I'm
referring; that's 1 in 68 my friend, so you'll have to give it a go from there.
Scott
| By Ed N (Ed_N) (acbfdd6d.ipt.aol.com - 172.191.221.109) on Wednesday, August 07, 2002 - 12:47 pm: |
I'm surprised no one has mentioned this, since we're talking about TK intentionally using ciphertext characters to (mis)spell his name in the 340 code (one would think he'd take the time to actually spell it correctly). In the second block of the 408 cipher, line 8, characters 11, 12, 13, 16 and 17 spell backwards, very obviously, "IM GOD" (with a transposition of the "I" and "M," and with the Z symbol as the "O"). Since we know Z had a gigantic ego, it would seem that he used ciphertext characters to spell that out.
| By Howard Davis (Howard) (dsl-gte-10407-2.linkline.com - 64.30.209.40) on Wednesday, August 07, 2002 - 02:40 pm: |
Ed ,
CM said he was God too!Well,throw in Jesus Christ,Buddha,Satan,Abraxes,etc.too!
| By Zander Kite (Zk) (dialup-166.90.117.113.dial1.nashville1.level3.net - 166.90.117.113) on Wednesday, August 07, 2002 - 03:36 pm: |
Scott, with your system, you've found "ALLEN" out of these letters: NSEZAPBVXWFABOTRTRUYSWVZEGYKETYALHFBXXADLPORXFGZJTJIBPQWVEXWIEHMUI. That's some creative code sleuthery! How did you manage to pull that off? I'm at a loss for words! Zander Kite is in there too! Anyone else see their name?? Now if you also count backwards letters, include: KCF(by the way, that's the first 3!-Did Allen like to go to KFC?? (maybe he liked to call it Kentucky Chicken Fried?). list continued: PECCDQEDECQRRK. I'm only asking one to find suspicious that the last 9 symbols that are forward or backward letters of the 340 code are NPKSZOAIK. Wow!, I never really looked at it that way, but the 13 last symbols as letters used close with NPKS-ZO-AIK-- or KAZNSKI OP.
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Wednesday, August 07, 2002 - 05:02 pm: |
Scott,
Thanks. You have now provided an algorithm for finding ciphertext ALLEN in part 3
of the 3-part cipher, which is completely analogous to the algorithm I presented to start
this thread. Since you have a pretty clearcut system, we should now be able to calculate
the odds.
Your system is: draw 136 characters (out of the 408 characters in the 3 part cipher), and
amoung these 136 characters of ciphertext, how often will they contain ALLEN by pure
chance?
To calculate the odds using my program I would require an ASCII tablulation of all the
Ciphertext characters in the 3 Part Cipher which you feel are obvious letters (if you wish
to compare with my calculation you could include all backward letters, circular characters
as "O", etc.)
If you can provide this, I'll do the calculation rigorously, however one can already see
the answer we'll get pretty clearly by looking at the other two parts of the 3-part
cipher: BOTH of them also contain ALLEN, so my guess is that it would be rather difficult
to draw 136 random characters and NOT find ALLEN, due to the commonness of A,L,E & N
in the ciphertext. Thus I suspect these odds are in fact close to 1 to 1.
You point out that AEN can be found in the first line, so perhaps you would like to
redifine your algorithm more strictly. Let us say this:
1.) Draw 136 characters randomly
2.) Find ALLEN, with at least three of those characters coming from the first line.
Here the odds would be lower. I could work them out if you give me an ASCII version of the
entire 408 cipher. Here's a quick way to gauge the odds of this restricted definition: How
many lines of the cipher contain 3 of the letters in ALLEN? It looks to me like about 1/4
of them do. I would guess that even with this restricted definition, the odds of finding
ALLEN by pure chance would be 1 in 10 to 1 in 100. Just a guess.
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Wednesday, August 07, 2002 - 05:23 pm: |
Ed: Regarding TK not spelling his name correctly, note that Zodiac did not spell
Zodiac correctly in the 340-cipher. Also, if any of the Ciphers, including the 340
contained an exact anagram of ANY suspect's full name in undiguised ciphertext, you can
bet that that suspect would quickly be under arrest. Clearly Z wanted to avoid this.
THEODORE is spelled correctly, but only after "obvious" substitutions are made
for the "O"s & backward-D.
If just THEODORE had appeared without these substitutions, you can bet the FBI would have
searched for socially mal-adjusted Theodore's in the Bay Area who knew about Radians &
the unit circle.....where do you suppose that would have led them?
Regarding "IMGOD": Nice find! Perhaps God should be included on Tom's list of
suspects.;) S/He is a known serial killer, of sorts.
| By Zander Kite (Zk) (dialup-166.90.117.4.dial1.nashville1.level3.net - 166.90.117.4) on Wednesday, August 07, 2002 - 08:15 pm: |
Obiwan, Scott can't seem to settle on where he wants to find ALLEN. Originally, it was
in the first 13 symbols(and letters)of the first line of the third block. Then he cleverly
adopted the symbol "L's" from the entire block. Apparently he finally realized
that "Kazinski" used only raw symbols. I like the part where he says that ALLEN
is spelled backwards to a tee in the first line except for the missing L's. Obiwan writes:
Thus I suspect that these odds are in fact close to 1 to 1. I agree, like you've said,
it's not hard to figure that out! I know you might have been tempted by the suggested 68
to 1 base, afterall 136/2=68! Taking something, that's already ridiculously strained,
further, would be a waste though. Scott could request the odds of ALLEN placed in a block
whereas the A is the 13th spot, L=66th L=82nd E=6th N=1st. It's million to one odds. Then
he associates the name ALLEN with million to one odds. You see, that's the kind of garbage
he's trying to produce here. Anything'll do.
Obiwan, I agree with you on how you described why Kaczynski wouldn't want to communicate
his name perfectly. I'm guessing that The Zodiac was aware of how the last line of his
first code was shredded for names. At any rate, Ted was a math man so I'm sure he realized
that full and complete name equals jail cell. Hey, I had a professor and he quit sometime
before the last summer when those kids were shot and wow I can read Theodore Kaczynski
just as plain as day matched to the first and last lines of The Zodiacs latest code. I
wonder about that? Ok, what's the number? However, touch it up a little and greatly reduce
the risk, yet still slip your name into the front page and laugh at the police.
| By Scott Bullock (Scott_Bullock) (coral.tci.com - 198.178.8.81) on Thursday, August 08, 2002 - 01:03 am: |
"You see, that's the kind of garbage [Scott's] trying to produce here. Anything'll
do."
Tell me about it. You can't find a single shred of evidence against TK, direct,
circumstantial, or otherwise, so you are forced to come to some esoteric conclusion that
doesn't mean squat. You've still got your figures all messed-up but that is okay. Like I
said in one of my first posts on this thread, "I can find Allen's last name in the
first line of the 3-part cipher and it took me all of 9 seconds."
I just knew you'd fall all over yourself trying to prove me wrong, Zander. That's what
makes this whole mess so amusing: I really did find Allen's name in about 9 seconds just
to show how ridiculous your conclusion concerning the 340-character cipher is. If you
really want anybody without rose-colored glasses to take your work seriously, you'd be
better off addressing those issues I've brought up in "The Book of the Dead"
thread. However, I doubt I'll be hearing from you over there because it will demand that
you demonstrate the use of real logic instead of insignificant BS such as that you have
demonstrated with regard to the 340-character cipher.
I'd love to hear what you have to say in the other cipher thread I created, Obiwan. At
least you have shown the ability to remain objective despite your convictions concerning
TK. Take the blinders off, Zander; there is nothing, and I mean nothing which even
remotely suggests that TK was the Zodiac.
See y'all in the funny papers.
Scott
| By Ed N (Ed_N) (acc1562e.ipt.aol.com - 172.193.86.46) on Thursday, August 08, 2002 - 11:46 am: |
obiwan: I certainly wouldn't put it that way. However, in this day and age, with so much New Age philosophy that preaches we are all God, that would mean that anyone and everyone is a suspect. However, I'd look for suspects that had a holier-than-thou attitude first...
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Thursday, August 08, 2002 - 11:53 pm: |
Ed: My "God" comment was intended toungue in cheek. Regarding Him/Her being a serial killer, I was thinking of sodom & gomora, and I'm sure there are other examples. In anycase I think you are right, looking for suspects with ego problems is a good idea. Many people with bragadocious egos are infact simply trying to mask massive insecurity, so we should look for both of these.
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Friday, August 09, 2002 - 12:02 am: |
Scott: Yes, I have realized all along (and I would hope that others realize this too) that you were not serious in proposing your "ALLEN" theory, that in fact it was a straw-man, designed to show that a totally different name could be found by a similar method which I used to find THEODORE KACZYNSKI, with similarly long odds. However, based on our discussion up to now, I would say that this has not been shown. If you would like to present other methods for finding "ALLEN" or any other name, than those mentioned above, I'd be willing to conduct a fair comparison.
| By Lapumo (Lapumo) (p51-183.as1.clm.clonmel.eircom.net - 159.134.51.183) on Friday, August 09, 2002 - 12:34 pm: |
Obiwan,
Three questions:-
1.If I had another name with a similar amount of letters and you calculate the odds,what
would it show or prove to you?
2.If I had a shorter name,amounting to long odds
but not as high as Kaczynski's,what do you think that would show?
3.If I have no other name what does the original "find" amount to?.(your view).
| By obiwan (Obiwan) (ciw2.ciw.edu - 192.70.249.40) on Friday, August 09, 2002 - 05:45 pm: |
Lapumo,
1.) Suppose we consider another 17 letter name, say SALVADORE PARADISO. I just ran this
name and the odds of randomly drawing 1 line which closely matches SALVADORE are less than
10,000 to 1 and the odds of matching PARADISO, are around 1%, for a combined total of 1
million to 1. We would thus not expect to find this name on single lines of the cipher
text randomly, and indeed we do not. As far as I know there are NO OTHER NAMES, of similar
length which can be found each on a single line of ciphertext. But I have not explored
other names yet.
2